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प्रश्न
Find the equation of the side BC of the triangle ABC whose vertices are (−1, −2), (0, 1) and (2, 0) respectively. Also, find the equation of the median through (−1, −2).
उत्तर
The vertices of triangle ABC are A (−1, −2), B (0, 1) and C (2, 0).
So, the equation of BC is
\[y - 1 = \frac{0 - 1}{2 - 0}\left( x - 0 \right)\]
\[ \Rightarrow y - 1 = \frac{- 1}{2}\left( x - 0 \right)\]
\[ \Rightarrow 2y - 2 = - x\]
\[ \Rightarrow x + 2y - 2 = 0\]
Let D be the midpoint of BC.
\[\therefore D \equiv \left( \frac{0 + 2}{2}, \frac{1 + 0}{2} \right) \equiv \left( 1, \frac{1}{2} \right)\]
So, the equation of median AD is
\[y + 2 = \frac{\frac{1}{2} + 2}{1 + 1}\left( x + 1 \right)\]
\[y + 2 = \frac{5}{4}\left( x + 1 \right)\]
\[ \Rightarrow 4y + 8 = 5x + 5\]
\[ \Rightarrow 5x - 4y - 3 = 0\]
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