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प्रश्न
Reduce the following equation into intercept form and find their intercepts on the axes.
4x – 3y = 6
उत्तर
The given equation is 4x – 3y = 6.
It can be written as
`(4"x")/6 - (3"y")/6 = 1`
`(2"x")/3 - "y"/2 = 1`
i.e., `"x"/((3/2)) + "y"/(-2) = 1` ...........(1)
This equation is of the form `"x"/"a" + "y"/"b" = 1`, where a = `3/2` and b = −2.
Therefore, equation (1) is in the intercept form, where the intercepts on the x and y axes are `3/2` and −2 respectively.
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