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प्रश्न
Reduce the following equation to the normal form and find p and α in y − 2 = 0.
उत्तर
y − 2 = 0
\[\Rightarrow y = 2\]
\[ \Rightarrow 0 \times x + y = 2\]
\[ \Rightarrow \frac{0 \times x}{\sqrt{0^2 + 1^2}} + \frac{y}{\sqrt{0^2 + 1^2}} = \frac{2}{\sqrt{0^2 + 1^2}} \left[ \text { Dividing both sides by } \sqrt{\left( \text { coefficient of x } \right)^2 + \left( \text { coefficient of y } \right)^2} \right]\]
\[ \Rightarrow 0 \times x + y = 2\]
This is the normal form of the given line, where p = 2,
\[\text { cos }\alpha = 0\] and \[\text { sin }\alpha = 1 \Rightarrow \alpha = {90}^\circ\].
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