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प्रश्न
Find the equation of the line joining the point (3, 5) to the point of intersection of the lines 4x + y − 1 = 0 and 7x − 3y − 35 = 0.
उत्तर
We have,
4x + y − 1 = 0 ... (1)
7x − 3y − 35 = 0 ... (2)
Solving (1) and (2) using cross-multiplication method:
\[\frac{x}{- 35 - 3} = \frac{y}{- 7 + 140} = \frac{1}{- 12 - 7}\]
\[ \Rightarrow x = 2, y = - 7\]
Thus, the point of intersection of the given lines is \[\left( 2, - 7 \right)\].
So, the equation of the line joining the points (3, 5) and \[\left( 2, - 7 \right)\] is
\[y - 5 = \frac{- 7 - 5}{2 - 3}\left( x - 3 \right)\]
\[ \Rightarrow y - 5 = 12x - 36\]
\[ \Rightarrow 12x - y - 31 = 0\]
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