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प्रश्न
Find the equation of a line which passes through the point (2, 3) and makes an angle of 30° with the positive direction of x-axis.
उत्तर
Here the slope of the line is m = tan θ
= tan 30°
= `1/sqrt(3)`
And the given point is (2, 3).
Therefore, using point-slope formula of the equation of a line
We have y – 3 = `1/sqrt(3) (x - 2)`
or `x - sqrt(3y) + (3sqrt(3) - 2)` = 0.
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