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प्रश्न
Find n, if (n + 1)! = 42 × (n – 1)!
उत्तर
(n + 1)! = 42 × (n – 1)!
∴ (n + 1) n (n – 1)! = 42 × (n – 1)!
∴ n2 + n = 42
∴ n (n + 1) = 6 × 7
Comparing on both side, we get
∴ n = 6
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