Advertisements
Advertisements
प्रश्न
Find n, if `"n"/(6!) = 4/(8!) + 3/(6!)`
उत्तर
`"n"/(6!) = 4/(8!) + 3/(6!)`
∴ `"n"/(6!)-3/(6!)=4/(8!)`
∴ `("n"-3)/(6!)=4/(8 xx 7 xx 6!)`
∴ n − 3 = `4/(8xx7)`
∴ n − 3 = `1/14`
∴ n = `1/14+3=(43)/(14)`
APPEARS IN
संबंधित प्रश्न
A teacher wants to select the class monitor in a class of 30 boys and 20 girls. In how many ways can he select a student if the monitor can be a boy or a girl?
A teacher wants to select the class monitor in a class of 30 boys and 20 girls, in how many ways can the monitor be selected if the monitor must be a boy? What is the answer if the monitor must be a girl?
How many five-digit numbers formed using the digit 0, 1, 2, 3, 4, 5 are divisible by 3 if digits are not repeated?
Evaluate: 8!
Evaluate: 8! – 6!
Evaluate: (8 – 6)!
Compute: `(12!)/(6!)`
Compute: `(12/6)!`
Compute: 3! × 2!
Compute: `(9!)/(3! 6!)`
Compute: `(6! - 4!)/(4!)`
Write in terms of factorial:
6 × 7 × 8 × 9
Find n, if (n + 1)! = 42 × (n – 1)!
Find n if: `("n"!)/(3!("n" - 3)!) : ("n"!)/(5!("n" - 5)!)` = 5:3
Find n, if: `((2"n")!)/(7!(2"n" - 7)!) : ("n"!)/(4!("n" - 4)!)` = 24:1
Show that
`("n"!)/("r"!("n" - "r")!) + ("n"!)/(("r" - 1)!("n" - "r" + 1)!) = (("n" + 1)!)/("r"!("n" - "r" + 1)!`
Find the value of: `(5(26!) + (27!))/(4(27!) - 8(26!)`
A question paper has 6 questions. How many ways does a student have if he wants to solve at least one question?
