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Show thatn!r!(n-r)!+n!(r-1)!(n-r+1)!=(n+1)!r!(n-r+1)! - Mathematics and Statistics

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प्रश्न

Show that
`("n"!)/("r"!("n" - "r")!) + ("n"!)/(("r" - 1)!("n" - "r" + 1)!) = (("n" + 1)!)/("r"!("n" - "r" + 1)!`

योग

उत्तर

L.H.S = `("n"!)/("r"!("n" - "r")!) + ("n"!)/(("r" - 1)!("n" - "r" + 1)!)`

`=("n"!)/("r"("r" - 1)!("n" - "r")!) + ("n"!)/(("r" - 1)! xx ("n" - "r" + 1)("n" - "r")!`

= `("n"!)/(("r" - 1)!("n" - "r")!)  [1/"r" + 1/("n" - "r" + 1)]`

= `("n"!)/(("r" - 1)!("n" - "r")!)  [("n" - "r" + 1 + "r")/("r"("n" - "r" + 1))]`

= `("n"!.("n" + 1))/["r"("r" - 1)!("n" - "r" + 1)("n" - "r")!)`

= `(("n" + 1)!)/("r"!("n" - "r" + 1)!]` = R.H.S.

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Concept of Factorial Function
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Permutations and Combinations - Exercise 6.2 [पृष्ठ ७६]

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बालभारती Mathematics and Statistics 2 (Commerce) [English] 11 Standard Maharashtra State Board
अध्याय 6 Permutations and Combinations
Exercise 6.2 | Q 11 | पृष्ठ ७६
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