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प्रश्न
Compute: `(6! - 4!)/(4!)`
उत्तर
`(6! - 4!)/(4!)`
= `(6 xx 5 xx 4! - 4!)/(4!)`
= `(4!(6 xx 5 - 1))/(4!)`
= 30 – 1
= 29
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संबंधित प्रश्न
A teacher wants to select the class monitor in a class of 30 boys and 20 girls, in how many ways can the monitor be selected if the monitor must be a boy? What is the answer if the monitor must be a girl?
Evaluate: 8! – 6!
Compute: `(12!)/(6!)`
Write in terms of factorial:
5 × 6 × 7 × 8 × 9 × 10
Write in terms of factorial:
3 × 6 × 9 × 12 × 15
Write in terms of factorial:
6 × 7 × 8 × 9
Evaluate: `("n"!)/("r"!("n" - "r"!)` For n = 8, r = 6
Find n, if `"n"/(6!) = 4/(8!) + 3/(6!)`
Find n, if (n + 1)! = 42 × (n – 1)!
Find n if: `("n"!)/(3!("n" - 3)!) : ("n"!)/(5!("n" - 5)!)` = 5:3
Find n if: `("n"!)/(3!("n" - 5)!) : ("n"!)/(5!("n" - 7)!)` = 10:3
Find n, if: `((17 - "n")!)/((14 - "n")!)` = 5!
Find n, if: `((15 - "n")!)/((13 - "n")!)` = 12
Find n, if: `((2"n")!)/(7!(2"n" - 7)!) : ("n"!)/(4!("n" - 4)!)` = 24:1
Show that: `(9!)/(3!6!) + (9!)/(4!5!) = (10!)/(4!6!)`
Find the value of: `(8! + 5(4!))/(4! - 12)`
Find the value of: `(5(26!) + (27!))/(4(27!) - 8(26!)`
A student passes an examination if he/she secures a minimum in each of the 7 subjects. Find the number of ways a student can fail.
