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Find the equation of the set of all points the sum of whose distances from the points (3, 0) and (9, 0) is 12. - Mathematics

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प्रश्न

Find the equation of the set of all points the sum of whose distances from the points (3, 0) and (9, 0) is 12.

योग

उत्तर

Let (x, y) be any point.

Given points are (3, 0) and (9, 0)

We have `sqrt((x - 3)^2 + (y - 0)^2) + sqrt((x - 9)^2 + (y - 0)^2)` = 12

⇒ `sqrt(x^2 + 9 - 6x + y^2) + sqrt(x^2 + 81 - 18x + y^2)` = 12

Putting x2 + 9 – 6x + y2 = k

⇒ `sqrt(k) + sqrt(72 - 12x + k)` = 12

⇒ `sqrt(72 - 12x + k) = 12 - sqrt(k)`

Squaring both sides, we have

⇒ 72 – 12x + k = `144 + k - 24sqrt(k)`

⇒ `24sqrt(k)` = 144 – 72 + 12x

⇒ `24sqrt(k)` = 72 + 12x

⇒ `2sqrt(k)` = 6 + x

Again squaring both sides, we get

4k = 36 + x2 + 12x

Putting the value of k, we have

4(x2 + 9 – 6x + y2) = 36 + x2 + 12x

⇒ 4x2 + 36 – 24x + 4y2 = 36 + x2 + 12x

⇒ 3x2 + 4y2 – 36x = 0

Hence, the required equation is 3x2 + 4y2 – 36x = 0.

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अध्याय 11: Conic Sections - Exercise [पृष्ठ २०४]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
अध्याय 11 Conic Sections
Exercise | Q 29 | पृष्ठ २०४

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