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An equilateral triangle is inscribed in the parabola y2 = 4 ax, where one vertex is at the vertex of the parabola. Find the length of the side of the triangle. - Mathematics

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प्रश्न

An equilateral triangle is inscribed in the parabola y2 = 4 ax, where one vertex is at the vertex of the parabola. Find the length of the side of the triangle.

योग

उत्तर

Parabola y2 = 4ax, an equilateral triangle is formed.

Let the length of its side be p.

ΔOLP in OL2 = OP2 + LP2

p2 = `"OP"^2 + ("p"/2)^2`

∴ OP2 = `"p"^2 - "p"^2/4 = 3/4"p"`

∴ The coordinates of L are `(sqrt3/2, "p"/2)`.

This parabola is situated at y2 = 4ax.

∴ `("p"/2)^2 = 4"a". (sqrt3/2"p")`

or `"p"^2/4 = 4"a" . sqrt3/2 "p"`

p = `8sqrt3"a"`

Hence, the length of the side of an equilateral triangle is `8sqrt3"a"`.

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अध्याय 11: Conic Sections - Miscellaneous Exercise [पृष्ठ २६४]

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एनसीईआरटी Mathematics [English] Class 11
अध्याय 11 Conic Sections
Miscellaneous Exercise | Q 8 | पृष्ठ २६४

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