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प्रश्न
Find the mean deviation about the median for the data.
36, 72, 46, 42, 60, 45, 53, 46, 51, 49
उत्तर
Writing the given data in ascending order
36, 42, 45, 46, 46, 49, 51, 53, 60, 72
n = 10
∴ `10/2` = 5th term = 46, and 5 + 1 = 6th term = 49
∴ Median = `(46 + 49)/2`
= `95/2`
= 47.5
| xi | |xi - 47.5| |
| 36 | 11.5 |
| 42 | 5.5 |
| 45 | 2.5 |
| 46 | 1.5 |
| 46 | 1.5 |
| 49 | 1.5 |
| 51 | 3.5 |
| 53 | 5.5 |
| 60 | 12.5 |
| 72 | 24.5 |
| Total | 70 |
Mean deviation (M) = `(sum|x_i - "M"|)/n`
= `70/70`
= 7
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