हिंदी

Calculate the Mean Deviation of the Following Income Groups of Five and Seven Members from Their Medians:Iincome in Rs.Iiincome in Rs.40004200440046004800 300400042004400460048005800 - Mathematics

Advertisements
Advertisements

प्रश्न

Calculate the mean deviation of the following income groups of five and seven members from their medians:

I
Income in Rs.
II
Income in Rs.
4000
4200
4400
4600
4800

 
 300
4000
4200
4400
4600
4800
5800

उत्तर

Calculate the mean deviation for the first data set.
The data is already arranged in ascending order.
For this data set, n is equal to 5.
Also, median, 

M = 4400

\[MD = \frac{1}{n} \sum^n_{i = 1} \left| d_i \right|, \text{ where } \left| d_i \right| = \left| x_i - M \right|\]

\[x_i\]
\[\left| d_i \right| = \left| x_i - M \right|\]
4000 400
4200 200
4400 0
4600 200
4800 400
Total 1200

\[MD = \frac{1}{5} \times 1200 = 240\]

Therefore, for the income of families in the first group, the mean deviation from the median is Rs 240.
Now, consider the second data set. This is also arranged in ascending order.
Here,

n = 7.

Also, median,

M= 4400
xi
\[\left| d_i \right| = \left| x_i - M \right|\]
300 4100
4000 400
4200 200
4400 0
4600 200
4800 400
5800 1400
Total 6700

\[MD = \frac{1}{7} \times 6700 = 957 . 14\]

Therefore, for the income of families in the second group, the mean deviation from the median is Rs 957.14.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 32: Statistics - Exercise 32.1 [पृष्ठ ६]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 11
अध्याय 32 Statistics
Exercise 32.1 | Q 3 | पृष्ठ ६

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Find the mean deviation about the mean for the data.

4, 7, 8, 9, 10, 12, 13, 17


Find the mean deviation about the mean for the data.

38, 70, 48, 40, 42, 55, 63, 46, 54, 44


Find the mean deviation about the mean for the data.

xi 10 30 50 70 90
fi 4 24 28 16 8

Calculate the mean deviation about median age for the age distribution of 100 persons given below:

Age Number
16 - 20 5
21 - 25 6
26 - 30 12
31 - 35 14
36 - 40 26
41 - 45 12
46 - 50 16
51 - 55 9

Calculate the mean deviation about the median of the observation:

 38, 70, 48, 34, 63, 42, 55, 44, 53, 47

 

Calculate the mean deviation from the mean for the  data:

(iv) 36, 72, 46, 42, 60, 45, 53, 46, 51, 49

 

Calculate the mean deviation from the mean for the  data:

 38, 70, 48, 40, 42, 55, 63, 46, 54, 44a


The lengths (in cm) of 10 rods in a shop are given below:
40.0, 52.3, 55.2, 72.9, 52.8, 79.0, 32.5, 15.2, 27.9, 30.2
 Find mean deviation from median


Find the mean deviation from the mean for the data:

xi 5 7 9 10 12 15
fi 8 6 2 2 2 6

Find the mean deviation from the median for the  data:

xi 15 21 27 30 35
fi 3 5 6 7 8

 


Find the mean deviation from the median for the data: 

xi 74 89 42 54 91 94 35
fi 20 12 2 4 5 3 4

Compute the mean deviation from the median of the following distribution:

Class 0-10 10-20 20-30 30-40 40-50
Frequency 5 10 20 5 10

Find the mean deviation from the mean for the data:

Classes 0-100 100-200 200-300 300-400 400-500 500-600 600-700 700-800
Frequencies 4 8 9 10 7 5 4 3

 


Find the mean deviation from the mean for the data:

Classes 95-105 105-115 115-125 125-135 135-145 145-155
Frequencies 9 13 16 26 30 12

 


The age distribution of 100 life-insurance policy holders is as follows:

Age (on nearest birth day) 17-19.5 20-25.5 26-35.5 36-40.5 41-50.5 51-55.5 56-60.5 61-70.5
No. of persons 5 16 12 26 14 12 6 5

Calculate the mean deviation from the median age


Find the mean deviation from the mean and from median of the following distribution:

Marks 0-10 10-20 20-30 30-40 40-50
No. of students 5 8 15 16 6

Calculate the mean deviation about the mean for the following frequency distribution:
 

Class interval: 0–4 4–8 8–12 12–16 16–20
Frequency 4 6 8 5 2

A batsman scores runs in 10 innings as 38, 70, 48, 34, 42, 55, 63, 46, 54 and 44. The mean deviation about mean is


The mean deviation of the numbers 3, 4, 5, 6, 7 from the mean is


The mean deviation for n observations \[x_1 , x_2 , . . . , x_n\]  from their mean \[\bar{X} \]  is given by

 
  

Find the mean deviation about the mean of the following data:

Size (x): 1 3 5 7 9 11 13 15
Frequency (f): 3 3 4 14 7 4 3 4

Calculate the mean deviation about the mean of the set of first n natural numbers when n is an odd number.


Calculate the mean deviation about the mean of the set of first n natural numbers when n is an even number.


Mean and standard deviation of 100 items are 50 and 4, respectively. Find the sum of all the item and the sum of the squares of the items.


Find the mean and variance of the frequency distribution given below:

`x` 1 ≤ x < 3 3 ≤ x < 5 5 ≤ x < 7 7 ≤ x < 10
`f` 6 4 5 1

Mean deviation for n observations x1, x2, ..., xn from their mean `barx` is given by ______.


The mean of 100 observations is 50 and their standard deviation is 5. The sum of all squares of all the observations is ______.


If `barx` is the mean of n values of x, then `sum_(i = 1)^n (x_i - barx)` is always equal to ______. If a has any value other than `barx`, then `sum_(i = 1)^n (x_i - barx)^2` is ______ than `sum(x_i - a)^2`


The sum of squares of the deviations of the values of the variable is ______ when taken about their arithmetic mean.


Let X = {x ∈ N: 1 ≤ x ≤ 17} and Y = {ax + b: x ∈ X and a, b ∈ R, a > 0}. If mean and variance of elements of Y are 17 and 216 respectively then a + b is equal to ______.


Find the mean deviation about the mean for the data.

xi 5 10 15 20 25
fi 7 4 6 3 5

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×