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Question
Calculate the mean deviation of the following income groups of five and seven members from their medians:
I Income in Rs. |
II Income in Rs. |
4000 4200 4400 4600 4800 |
300 4000 4200 4400 4600 4800 5800 |
Solution
Calculate the mean deviation for the first data set.
The data is already arranged in ascending order.
For this data set, n is equal to 5.
Also, median,
M = 4400
\[MD = \frac{1}{n} \sum^n_{i = 1} \left| d_i \right|, \text{ where } \left| d_i \right| = \left| x_i - M \right|\]
\[x_i\]
|
\[\left| d_i \right| = \left| x_i - M \right|\]
|
4000 | 400 |
4200 | 200 |
4400 | 0 |
4600 | 200 |
4800 | 400 |
Total | 1200 |
\[MD = \frac{1}{5} \times 1200 = 240\]
Therefore, for the income of families in the first group, the mean deviation from the median is Rs 240.
Now, consider the second data set. This is also arranged in ascending order.
Here,
n = 7.
Also, median,
xi |
\[\left| d_i \right| = \left| x_i - M \right|\]
|
300 | 4100 |
4000 | 400 |
4200 | 200 |
4400 | 0 |
4600 | 200 |
4800 | 400 |
5800 | 1400 |
Total | 6700 |
\[MD = \frac{1}{7} \times 6700 = 957 . 14\]
Therefore, for the income of families in the second group, the mean deviation from the median is Rs 957.14.
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