हिंदी

Give example of a situation in which an applied force does not result in a change in kinetic energy. - Physics

Advertisements
Advertisements

प्रश्न

Give example of a situation in which an applied force does not result in a change in kinetic energy.

टिप्पणी लिखिए

उत्तर

Assume a ball is tied to a string and is moving in a vertical circle. Work done by tension force will be zero and hence tension force will not cause any change in KE of the ball. Because at any instant of time the displacement is tangential and the force is central in nature, i.e., the tension in the string and the small displacement at any instant are perpendicular to each other.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Work, Energy and Power - Exercises [पृष्ठ ४६]

APPEARS IN

एनसीईआरटी एक्झांप्लर Physics [English] Class 11
अध्याय 6 Work, Energy and Power
Exercises | Q 6.31 | पृष्ठ ४६

संबंधित प्रश्न

In Figure (i) the man walks 2 m carrying a mass of 15 kg on his hands. In Figure (ii), he walks the same distance pulling the rope behind him. The rope goes over a pulley, and a mass of 15 kg hangs at its other end. In which case is the work done greater?


Is work-energy theorem valid in non-inertial frames?

 

A ball is given a speed v on a rough horizontal surface. The ball travels through a distance l on the surface and stops. what are the initial and final kinetic energies of the ball?  


The US athlete Florence Griffith-Joyner won the 100 m sprint gold medal at Seoul Olympics in 1988, setting a new Olympic record of 10⋅54 s. Assume that she achieved her maximum speed in a very short time and then ran the race with that speed till she crossed the line. Take her mass to be 50 kg. Assuming that the track, wind etc. offered an average resistance of one-tenth of her weight, calculate the work done by the resistance during the run. 


In a factory, 2000 kg of metal needs to be lifted by an engine through a distance of 12 m in 1 minute. Find the minimum horsepower of the engine to be used.

 

A small block of mass 200 g is kept at the top of a frictionless incline which is 10 m long and 3⋅2 m high. How much work was required (a) to lift the block from the ground and put it an the top, (b) to slide the block up the incline? What will be the speed of the block when it reaches the ground if (c) it falls off the incline and drops vertically to the ground (d) it slides down the incline? Take g = 10 m/s2


A chain of length l and mass m lies on the surface of a smooth sphere of radius R > l with one end tied to the top of the sphere.  Find the gravitational potential energy of the chain with reference level at the centre of the sphere.


A bullet of mass m fired at 30° to the horizontal leaves the barrel of the gun with a velocity v. The bullet hits a soft target at a height h above the ground while it is moving downward and emerges out with half the kinetic energy it had before hitting the target.

Which of the following statements are correct in respect of bullet after it emerges out of the target?

  1. The velocity of the bullet will be reduced to half its initial value.
  2. The velocity of the bullet will be more than half of its earlier velocity.
  3. The bullet will continue to move along the same parabolic path.
  4. The bullet will move in a different parabolic path.
  5. The bullet will fall vertically downward after hitting the target.
  6. The internal energy of the particles of the target will increase.

A raindrop of mass 1.00 g falling from a height of 1 km hits the ground with a speed of 50 ms–1. Calculate 

  1. the loss of P.E. of the drop.
  2. the gain in K.E. of the drop.
  3. Is the gain in K.E. equal to a loss of P.E.? If not why.

Take g = 10 ms–2


A rocket accelerates straight up by ejecting gas downwards. In a small time interval ∆t, it ejects a gas of mass ∆m at a relative speed u. Calculate KE of the entire system at t + ∆t and t and show that the device that ejects gas does work = `(1/2)∆m u^2` in this time interval (neglect gravity).


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×