हिंदी

How is Propene Converted into 1- Bromopropane and 2 - Bromopropane? - Chemistry

Advertisements
Advertisements

प्रश्न

 How is propene converted into 1- bromopropane and 2 - bromopropane?

उत्तर

The addition of hydrogen halide to an unsymmetrical alkene gives two products.
Propene on reaction with hydrogen bromide forms 80% 2-bromopropane (isopropyl bromide) and 20% 1-bromopropane (n-propyl bromide).

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2015-2016 (March)

APPEARS IN

वीडियो ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्न

How do you convert the following: Prop-1-ene to 1-fluoropropane


Write the structure of the major product in each of the following reaction :


Write a short note on Sandmeyer’s reaction. 


Finkelstein reaction is ______.


Rectified spirit is a mixture of ____________.


The solution of a chemical compound reacts with AgNO3 solution to form a white precipitate of Y which dissolves in NH4OH to give a complex Z. When Z is treated with dilute HNO3, Y reappears. The chemical compound X can be:


Gem-dibromide is ____________.


\[\ce{X ->[AgNO3][HNO3] Yellow or While ppt}\]

Which of the following cannot be X?


The order of reactivity of alcohols with halogen acids is ______.

(A) \[\ce{CH3CH2 - CH2 - OH}\]

(B) \[\begin{array}{cc}
\phantom{}\ce{CH3CH2 - CH - OH}\\
\phantom{...}\phantom{}|\\
\phantom{......}\ce{CH3}
\end{array}\]

(C)  \[\begin{array}{cc}
\phantom{........}\ce{CH3}\\
\phantom{.....}\phantom{}|\\
\phantom{}\ce{CH3CH2 - C - OH}\\
\phantom{.....}\phantom{}|\\
\phantom{........}\ce{CH3}
\end{array}\]


Discuss the role of Lewis acids in the preparation of aryl bromides and chlorides in the dark.


Identify the products A and B formed in the following reaction:

\[\ce{CH3 - CH2 - CH = CH - CH3 + HCl -> A + B}\]


A hydrocarbon of molecular mass 72 g mol–1 gives a single monochloro derivative and two dichloro derivatives on photo chlorination. Give the structure of the hydrocarbon.


Which of the following compounds would undergo SN1 reaction faster and why?

(A) (B)

Which of the following is the most stable free radical?


Which compound would undergo dehydrohalogenation with strong base to give the alkene shown below as the only alkene product?

CH3 – CH2CH = CH – CH3


Which of the following species is an odd electron intermediate?


The most stable free radical among the following is


Which is gem-dihalide?


The alkyl halide which does not give white precipitate with alcoholic AgNO3 solution is :-


Benzoyl chloride is is prepared from benzoic acid by


SN1 and SN2 product are same with


\[\begin{array}{cc}
\ce{Ph - CH - CH2 - CH2 ->[Zn - Cu][Δ] Product}\\
\phantom{..}|\phantom{......}|\phantom{....................}\\
\phantom{}\ce{Br}\phantom{....}\ce{Br}\phantom{..................}
\end{array}\]

Product of the above reaction is


The major product of the following reaction is:


\[\ce{C2H5Cl + AgF -> C2H5F + AgCl}\] The above reaction is called ______.


The major product of the following reaction is:


In the given reactions sequence, the major product 'C' is:

\[\ce{C8H10 ->[HNO3][H2SO4] A ->[Br2][\Delta] B ->[alcoholic][KOH] C}\]


Arrange the following in increasing order of reactivity towards nitration

  1. p-xylene
  2. bromobenzene
  3. mesitylene
  4. nitrobenzene
  5. benzene

Choose the correct answer from the options given below:


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×