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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

How will you prepare the given compound from benzene? You may use any inorganic reagent and any organic reagent having not more than one carbon atom. Phenylacetic acid - Chemistry

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प्रश्न

How will you prepare the given compound from benzene? You may use any inorganic reagent and any organic reagent having not more than one carbon atom.

Phenylacetic acid

रासायनिक समीकरण/संरचनाएँ

उत्तर

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अध्याय 12: Aldehydes, Ketones and Carboxylic Acids - Exercises [पृष्ठ ३७८]

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एनसीईआरटी Chemistry [English] Class 12
अध्याय 12 Aldehydes, Ketones and Carboxylic Acids
Exercises | Q 14.4 | पृष्ठ ३७८

संबंधित प्रश्न

On acid hydrolysis, propane nitrile gives.


How is carbolic acid prepared from chlorobenzene?


Write the structures of A and B in the following reactions


Show how the following compound can be converted to benzoic acid.

Acetophenone


Predict the products formed when cyclohexanecarbaldehyde reacts with the following reagent.

Tollens’ reagent


How will you prepare the given compound from benzene? You may use any inorganic reagent and any organic reagent having not more than one carbon atom.

m-Nitrobenzoic acid


How will you prepare the given compound from benzene? You may use any inorganic reagent and any organic reagent having not more than one carbon atom.

p-Nitrobenzoic acid


How will you bring about the following conversion in not more than two steps?

Benazaldehyde to α-Hydroxyphenylacetic acid


How is methoxy benzene prepared from carbolic acid?


Name the reagents used in the following reactions:


What is the action of following reagents on glucose?
1. Bromine water
2. Hydroxylamine


The functional group present in triacylglycerol is _______.


Match the reactions given in Column I with the suitable reagents given in Column II.

Column I
(Reactions)
Column II
(Reagents)
(i) Benzophenone Diphenylmethane (a) \[\ce{LiAlH4}\]
(ii) Benzaldehyde 1-Phenylethanol (b) \[\ce{DIBAL-H}\]
(iii) Cyclohexanone Cyclohexanol (c) \[\ce{Zn(Hg)/Conc. HCl}\]
(iv) Phenyl benzoate Benzaldehyde (d) \[\ce{CH3MgBr}\]

Assertion: Aldehydes and ketones, both react with Tollen’s reagent to form silver mirror.

Reason: Both, aldehydes and ketones contain a carbonyl group.


Substitution of one alkyl group by replacing hydrogen of primary amines


The end product Y in the sequence of reaction:

\[\ce{RX ->[CN^-] X ->[NaOH] Y}\] is:


Y is:


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