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If = [2a+b3a-bc+2d2c-d]=[234-1], find a, b, c and d. - Mathematics and Statistics

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प्रश्न

If = `[(2"a" + "b", 3"a" - "b"),("c" + 2"d", 2"c" - "d")] = [(2, 3),(4, -1)]`, find a, b, c and d.

योग

उत्तर

`[(2"a" + "b", 3"a" - "b"),("c" + 2"d", 2"c" - "d")] = [(2, 3),(4, -1)]`

By equality of matrices,

2a + b = 2     ...(1)

3a – b = 3   ...(2)

c + 2d = 4    ...(3)

2c – d = – 1  ...(4)

Adding (1) and (2), we get,

5a = 5

∴ a = 1

∴ from (1), b = 2 – 2a = 2 – 2 = 0

Multiplying equation (3) by 2, we get,

2c + 4d = 8

Subtracting equation (4) from this equation, we get,

5d = 9

∴d = `9/5`

∴ from (3), `"c" + 2(9/5)` = 4

∴ c = `4 - 18/5 = 2/5`

Hence, a = 1 , b = 0, c = `2/5 and "d" = 9/5`.

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अध्याय 4: Determinants and Matrices - Exercise 4.5 [पृष्ठ ८७]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board
अध्याय 4 Determinants and Matrices
Exercise 4.5 | Q 10 | पृष्ठ ८७

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