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प्रश्न
If AB, AC, PQ are tangents in Fig. and AB = 5cm find the perimeter of ΔAPQ.
उत्तर
Perimeter of ΔAPQ, (P) = AP + AQ + PQ
= AP + AQ + (PX + QX)
We know that
The two tangents drawn from external point to the circle are equal in length from point A,
AB = AC = 5 cm
From point P, PX = PB
From point Q, QX = QC
Perimeter (P) = AP + AQ + (PB + QC)
= (AP + PB) + (AQ + QC)
= AB + AC = 5 + 5
= 10 cms.
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