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If the Angles of Elevation of the Top of a Tower from Two Points Distant a and B from the Base and in the Same Straight Line with It Are Complementary, Then the Height of the Tower is - Mathematics

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प्रश्न

If the angles of elevation of the top of a tower from two points distant a and b from the  base and in the same straight line with it are complementary, then the height of the tower is 

विकल्प

  •  ab

  • \[\sqrt{ab}\]

  • \[\frac{a}{b}\]

  • \[\sqrt{\frac{a}{b}}\]

MCQ

उत्तर

Let h be the height of tower AB

Given that: angle of elevation of top of the tower are `∠D=θ`and .`∠C=90°-θ`

Distance`BC=b` and `BD=a`

Here, we have to find the height of tower.

So we use trigonometric ratios.

In a triangle, ABC

`tan D=(AB)/(BC)`  

`⇒ tan (90°-θ)=h/b`

`⇒ cotθ=h/b` 

Again in a triangle ABD

`tan D=(AB)/(BD)` 

`⇒ tan θ=h/a` 

`⇒1/cot θ=h/a` 

⇒ `b/h=h/a` 

`⇒h^2=ab`

`⇒ h=sqrt(ab)`

Put `cotθ=h/b `

 

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अध्याय 12: Trigonometry - Exercise 12.3 [पृष्ठ ४१]

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आरडी शर्मा Mathematics [English] Class 10
अध्याय 12 Trigonometry
Exercise 12.3 | Q 5 | पृष्ठ ४१

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