If P + 1 P = 6 ; Find : P 2 + 1 P 2 - Mathematics

If $p + \frac{1}{p} = 6$ ; find : $p^{2} + \frac{1}{p^{2}}$

योग

${(p + \frac{1}{p})}^{2}$

= $p^{2} + \frac{1}{p^{2}} + 2$

⇒ 36 = $p^{2} + \frac{1}{p^{2}} + 2$

⇒ $p^{2} + \frac{1}{p^{2}}$
= 36 - 2
= 34.

shaalaa.com

क्या इस प्रश्न या उत्तर में कोई त्रुटि है?

अध्याय 4: Expansions - Exercise 4.2

अध्याय 4 Expansions
Exercise 4.2 | Q 10.1

If $x - \frac{1}{x} = 7$ ,find the value of $x^{3} - \frac{1}{x^{3}}$

If a + b = 6 and ab = 20, find the value of a³ − b³

If $x + \frac{1}{x} = 2$ , then $x^{3} + \frac{1}{x^{3}} =$

If $x + \frac{1}{x} = 3$ then $x^{6} + \frac{1}{x^{6}}$ =

(x − y) (x + y) (x² + y²) (x⁴+ y⁴) is equal to

Find the square of : 3a - 4b

Use direct method to evaluate the following products :
(x + 8)(x + 3)

Simplify:

$(x - \frac{1}{x}) (x^{2} + 1 + \frac{1}{x^{2}})$

Using suitable identity, evaluate the following:

101 × 102

Factorise the following:

16x² + 4y² + 9z² – 16xy – 12yz + 24xz