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If R = {(x, y) : x, y ∈ Z, x2 + y2 ≤ 4} is a relation on Z, then the domain of R is ______. - Mathematics

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प्रश्न

If R = {(x, y) : x, y ∈ Z, x2 + y2 ≤ 4} is a relation on Z, then the domain of R is ______.

विकल्प

  • {0, 1, 2}

  • {0, −1, −2}

  • {−2, −1, 0, 1, 2}

  • {−1, 0, 1}

  • None of these

MCQ
रिक्त स्थान भरें

उत्तर

If R = {(x, y) : x, y ∈ Z, x2 + y2 ≤ 4} is a relation on Z, then the domain of R is {−2, −1, 0, 1, 2}.

Explanation:

R = {(x, y) : x, y ∈ Z, x2 + y2 ≤ 4}

We know that,

\[\Rightarrow \left( - 2 \right)^2 + 0^2 \leq 4\]

\[ \Rightarrow \left( 2 \right)^2 + 0^2 \leq 4\]

\[ \Rightarrow \left( - 1 \right)^2 + 0^2 \leq 4\]

\[ \Rightarrow \left( 1 \right)^2 + 0^2 \leq 4\]

\[ \Rightarrow \left( - 1 \right)^2 + \left( 1 \right)^2 \leq 4\]

\[ \Rightarrow 0^2 + 0^2 \leq 4\]

\[ \Rightarrow \left( 1 \right)^2 + \left( 1 \right)^2 \leq 4\]

\[ \Rightarrow \left( - 1 \right)^2 + \left( - 1 \right)^2 \leq 4\]

Hence, domain (R) = {−2, −1, 0, 1, 2}.

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अध्याय 2: Relations - Exercise 2.5 [पृष्ठ २५]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 2 Relations
Exercise 2.5 | Q 5 | पृष्ठ २५

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