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If Y = Cot X Show that D 2 Y D X 2 + 2 Y D Y D X = 0 ? - Mathematics

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प्रश्न

If y = cot x show that \[\frac{d^2 y}{d x^2} + 2y\frac{dy}{dx} = 0\] ?

उत्तर

Here,

\[y = \cot x\]

\[\text { Differentiating w . r . t . x, we get } \]

\[\frac{d y}{d x} = - {cosec}^2 x\]

\[\text { Differentiating again w . r . t . x, we get }\]

\[\frac{d^2 y}{d x^2} = - 2 \ cosec \ x \times \left( - cosec \ x \ cot \ x \right)\]

\[ \Rightarrow \frac{d^2 y}{d x^2} = 2  \ {cosec}^2 \ x \ cot x\]

\[ \Rightarrow \frac{d^2 y}{d x^2} = - 2y\frac{dy}{dx}\]

\[ \Rightarrow \frac{d^2 y}{d x^2} + 2y\frac{dy}{dx} = 0\]

Hence proved.

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अध्याय 12: Higher Order Derivatives - Exercise 12.1 [पृष्ठ १७]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 12 Higher Order Derivatives
Exercise 12.1 | Q 29 | पृष्ठ १७

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