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In ΔABC, B − D − C and BD = 7, BC = 20, then find the following ratio. (i) A(ΔABD)A(ΔADC)A(ΔABD)A(ΔADC) (ii) A(ΔABD)A(ΔABC)A(ΔABD)A(ΔABC) (iii) A(ΔADC)A(ΔABC)A(ΔADC)A(ΔABC) - Geometry Mathematics 2

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प्रश्न

In ΔABC, B − D − C and BD = 7, BC = 20, then find the following ratio.

(i) `"A(ΔABD)"/"A(ΔADC)"`

(ii) `"A(ΔABD)"/"A(ΔABC)"`

(iii) `"A(ΔADC)"/"A(ΔABC)"`

योग

उत्तर

Draw AE ⊥ BC, B – E – C.

BC = BD + DC       ......[B – D – C]

∴ 20 = 7 + DC

∴ DC = 20 − 7 = 13

(i) ΔABD and ΔADC have same height AE.

`"A(ΔABD)"/"A(ΔADC)" = "BD"/"DC"` .....[Triangles having equal height]

∴ `"A(ΔABD)"/"A(ΔADC)" = 7/13`

(ii) ΔABD and ΔABC have same height AE.

`"A(ΔABD)"/"A(ΔABC)" = "BD"/"BC"`   ......[Triangles having equal height]

∴ `"A(ΔABD)"/"A(ΔABC)" = 7/20`

(iii) ΔADC and ΔABC have same height AE.

`"A(ΔADC)"/"A(ΔABC)" = "DC"/"BC"`  ......[Triangles having equal height]

∴ `"A(ΔADC)"/"A(ΔABC)" = 13/20`

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अध्याय 1: Similarity - Q.3 (B)

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