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Let Q and W Denote the Amount of Heat Given to an Ideal Gas and the Work Done by It in an Isothermal Process. - Physics

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प्रश्न

Let Q and W denote the amount of heat given to an ideal gas and the work done by it in an isothermal process.

विकल्प

  • Q = 0

  •  W = 0

  • Q ≠ W

  • Q = W

MCQ

उत्तर

 Q = W

In an isothermal process, temperature of the system stays constant, i.e. there's no change in internal energy. Thus, U = 0, where U denotes the change in internal energy of the system. According to the first law of thermodynamics, heat supplied to the system is equal to the sum of change in internal energy and work done by the system, such that Q = U + W. As U = 0, Q = W.

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Interpretation of Temperature in Kinetic Theory - Introduction of Kinetic Theory of an Ideal Gas
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Specific Heat Capacities of Gases - MCQ [पृष्ठ ७७]

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एचसी वर्मा Concepts of Physics Vol. 2 [English] Class 11 and 12
अध्याय 5 Specific Heat Capacities of Gases
MCQ | Q 2 | पृष्ठ ७७

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