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प्रश्न
\[\lim_{x \to - 1} \frac{x^3 - 3x + 1}{x - 1}\]
उत्तर
\[\lim_{x \to - 1} \left( \frac{x^3 - 3x + 1}{x - 1} \right)\]
\[ = \frac{\left( - 1 \right)^3 - 3\left( - 1 \right) + 1}{- 1 - 1}\]
\[ = \frac{- 1 + 3 + 1}{- 2}\]
\[ = \frac{- 3}{2}\]
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