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Prove that (a→+b→).(a→+b→) = |a→|2+|b→|2 if and only if a→.b→ are perpendicular, given a→≠0→,b→≠0→. - Mathematics

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प्रश्न

Prove that `(veca + vecb).(veca + vecb)` = `|veca|^2 + |vecb|^2` if and only if `veca . vecb` are perpendicular, given `veca != vec0, vecb != vec0.`

योग

उत्तर

`(veca + vecb) xx (veca + vecb) = |veca|^2 + |vecb|^2`

`veca xx veca + veca xx vecb + vecb xx veca + vecb xx vecb = |veca|^2 + |vecb|^2`

`|veca|^2 + 2veca xx vecb + |b|^2 = |veca|^2 + |vecb|^2`

`2veca xx vecb = 0`

`veca xx vecb = 0`

`veca, vecb` are perpendicular.

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अध्याय 10: Vector Algebra - Exercise 10.5 [पृष्ठ ४५९]

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एनसीईआरटी Mathematics [English] Class 12
अध्याय 10 Vector Algebra
Exercise 10.5 | Q 15 | पृष्ठ ४५९

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