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Prove that angle bisector of any angle of a triangle and perpendicular bisector of the opposite side if intersect, they will intersect on the circumcircle of the triangle. - Mathematics

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प्रश्न

Prove that angle bisector of any angle of a triangle and perpendicular bisector of the opposite side if intersect, they will intersect on the circumcircle of the triangle.

योग

उत्तर

Given: ΔABC is inscribed in a circle. Bisector of ∠A and perpendicular bisector of BC intersect at point Q.

To prove: A, B, Q and C are con-cyclic.

Construction: Join BQ and QC.

Proof: We have assumed that, Q lies outside the circle.

In ΔBMQ and ΔCMQ,

BM = CM  ...[QM is the perpendicular bisector of BC]

∠BMQ = ∠CMQ   ...[Each 90°]

MQ = MQ   ...[Common side]

∴ ΔBMQ ≅ ΔCMQ  ...[By SAS congruence rule]

∴ BQ = CQ  [By CPCT] ...(i)

Also, ∠BAQ = ∠CAQ   [Given] ...(ii)

From equations (i) and (ii),

We can say that Q lies on the circle  ...[Equal chords of a circle subtend equal angles at the circumference]

Hence, A, B, Q and C are con-cyclic.

Hence proved.

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अध्याय 10: Circles - Exercise 10.4 [पृष्ठ १०६]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 9
अध्याय 10 Circles
Exercise 10.4 | Q 5. | पृष्ठ १०६

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