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Should the Energy of a Photon Be Called Its Kinetic Energy Or Its Internal Energy? - Physics

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प्रश्न

Should the energy of a photon be called its kinetic energy or its internal energy?

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उत्तर

Relativistic equation of energy :

`E^2 = p^2c^2 + m^2c^4`       ....(1)

Here, p2c2 = kinetic energy of photon
           m02c4 = internal energy of photon
We know photons have zero rest mass. Therefore, m0 = 0. Substituting the value of m0 = 0 in equation (1), we get : `E = pc`

Thus, the energy of a photon should be called its kinetic energy.

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Experimental Study of Photoelectric Effect
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 20: Photoelectric Effect and Wave-Particle Duality - Short Answers [पृष्ठ ३६३]

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एचसी वर्मा Concepts of Physics Vol. 2 [English] Class 11 and 12
अध्याय 20 Photoelectric Effect and Wave-Particle Duality
Short Answers | Q 6 | पृष्ठ ३६३

संबंधित प्रश्न

The photoelectric cut-off voltage in a certain experiment is 1.5 V. What is the maximum kinetic energy of photoelectrons emitted?


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Can we find the mass of a photon by the definition p = mv?


Is it always true that for two sources of equal intensity, the number of photons emitted in a given time are equal?


Can a photon be deflected by an electric field? Or by a magnetic field?


If an electron has a wavelength, does it also have a colour?


Let nr and nb be the number of photons emitted by a red bulb and a blue bulb, respectively, of equal power in a given time.


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(c) more energetic photons are emitted
(d) faster photons are emitted


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When the sun is directly overhead, the surface of the earth receives 1.4 × 103 W m−2 of sunlight. Assume that the light is monochromatic with average wavelength 500 nm and that no light is absorbed in between the sun and the earth's surface. The distance between the sun and the earth is 1.5 × 1011 m. (a) Calculate the number of photons falling per second on each square metre of earth's surface directly below the sun. (b) How many photons are there in each cubic metre near the earth's surface at any instant? (c) How many photons does the sun emit per second?

(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)


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(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)


Show that it is not possible for a photon to be completely absorbed by a free electron.


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(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)


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The figure shows the variation of photoelectric current measured in a photocell circuit as a function of the potential difference between the plates of the photocell when light beams A, B, C and D of different wavelengths are incident on the photocell. Examine the given figure and answer the following questions:

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  3. Which light beam ejects photoelectrons with maximum momentum and why?

How would the stopping potential for a given photosensitive surface change if the intensity of incident radiation was decreased? Justify your answer.


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