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प्रश्न
Show that:
The ratio of the areas of two triangles on the same base is equal to the ratio of their heights.
उत्तर
Consider the following figure :
Here
Ar. ( ΔABC ) = `1/2` BM x AC
and, Ar. ( ΔADC ) = `1/2` DN x AC
`["Area"( Δ"ABD")]/["Area(Δ ADC )"] = [1/2 "BM" xx "AC"]/[1/2 "DN" xx "AC"]= "BM"/"DN"`
hence proved
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संबंधित प्रश्न
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Show that these parallelograms are equal in the area.
[ Join B and R ]
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Prove that: Area of ABC = Area of // gm BDEC.
In the given figure, diagonals PR and QS of the parallelogram PQRS intersect at point O and LM is parallel to PS. Show that:
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(ii) Area (POS) + Area (QOR) = Area (// gm PQRS)
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Show that:
A diagonal divides a parallelogram into two triangles of equal area.
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Show that the area of quadrilateral EFGH is half of the area of parallelogram ABCD.
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prove that the ΔOBC and quadrilateral AEOF are equal in area.
Show that:
The ratio of the areas of two triangles of the same height is equal to the ratio of their bases.
