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Simplify: (a – b) (a2 + b2 + ab) – (a + b) (a2 + b2 – ab) - Mathematics

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प्रश्न

Simplify:

(a – b) (a2 + b2 + ab) – (a + b) (a2 + b2 – ab)

योग

उत्तर

We have,

(a – b) (a2 + b2 + ab) – (a + b) (a2 + b2 – ab) = a(a2 + b2 + ab) – b(a2 + b2 + ab) – a(a2 + b2 – ab) – b(a2 + b2 – ab)

= a3 + ab2 + a2b – ba2 – b3 – ab2 – a3 – ab2 + a2b – ba2 – b3 + ab2

= (a3 – a3) + (– b3 – b3) + (ab2 – ab2) + (a2b – a2b + a2b – a2b)

= 0 – 2b3 + 0 + 0 + 0

= – 2b3

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अध्याय 7: Algebraic Expression, Identities and Factorisation - Exercise [पृष्ठ २३१]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 8
अध्याय 7 Algebraic Expression, Identities and Factorisation
Exercise | Q 84. (ix) | पृष्ठ २३१

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