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Solve the Following Lpp Graphically: Maximize Z = 20 X + 10 Y Subject to the Following Constraints X + 2 Y ≤ 28 3x+ Y ≤ 24 X ≥ 2x. Y ≥ 0 - Mathematics

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प्रश्न

Solve the following LPP graphically:
Maximize Z = 20 x + 10 y 
Subject to the following constraints 

\[x +\]2\[y \leq\]28 
3x+ \[y \leq\]24 
\[x \geq\] 2x.
\[y \geq\]  0

योग

उत्तर

The given constraints are
x + 2y ≤ 28     

3x + y ≤ 24  
x ≥ 2       
xy ≥ 0              
Converting the given inequations into equations, we get
x + 2y = 28, 3x + y = 24, x = 2, x = 0 and = 0
These lines are drawn on the graph and the shaded region ABCD represents the feasible region of the given LPP.

It can be observed that the feasible region is bounded. The coordinates of the corner points of the feasible region are A(2, 13), B(2, 0), C(4, 12) and D(8, 0).

The values of the objective function, Z at these corner points are given in the following table:
 

Corner Point Value of the Objective Function Z = 20x + 10y
A(2, 13) Z = 20 × 2 + 10 × 13 = 170
B(2, 0) Z = 20 × 2 + 10 × 0 = 40
C(8, 0) Z = 20 × 8 + 10 × 0 = 160
D(4, 12) Z = 20 × 4 + 10 × 12 = 200 


From the table, is maximum at = 4 and y = 12 and the maximum value of is 200.

Thus, the maximum value of Z is 200.

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अध्याय 30: Linear programming - Exercise 30.2 [पृष्ठ ३३]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 30 Linear programming
Exercise 30.2 | Q 27 | पृष्ठ ३३

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