Advertisements
Advertisements
प्रश्न
State Einstein’s photoelectric equation. Explain all characteristics of the photoelectric effect, on the basis of Einstein’s photoelectric equation.
उत्तर
Einstein’s photoelectric equation: K.E.max = (hν – `phi_0`)
Characteristics of photoelectric effect:
- The photoelectric work function `phi_0` is constant for a given emitter. Hence if the frequency ‘ν’ of the incident radiation is decreased, the maximum kinetic energy of the emitted photoelectrons decreases, till it becomes zero for a certain frequency ν0. Therefore, from Einstein’s equation,
0 = hv0 - `phi_0`
∴ `phi_0` = hv0 .......….(1)
This shows that the threshold frequency is related to the work function of the metal and hence it has different values for different metals. - Using equation (1), Einstein’s equation can be written as
`1/2"mv"_"max"^2 = "hv" - "hv"_0`
∴ `1/2"mv"_"max"^2 = "h"("v" - "v"_0)`
This equation shows that:
a. If ν < ν0, then K.E is negative, which is not possible. In this case, photoelectric emission is not possible.
b. If ν > ν0, then photoelectrons move with some velocity.
∴ K.E > 0, which is possible. Hence, photoelectrons are emitted.
c. If ν = ν0, the photoelectrons are just emitted. In this case, K.E = 0. - The photoelectric equation is,
`1/2"mv"_"max"^2 = "hv" - phi_0` .....….(2)
where, hν = energy of the photon of incident radiation.
`phi_0 = "hv"_0` = photoelectric work function of the metal.
Thus, both the terms on the R.H.S of equation (2) depends on the frequency and not on the intensity of radiation. Hence the maximum kinetic energy with which photoelectrons are emitted is independent of the intensity of radiation. However, since `phi_0` and h are constants, the maximum kinetic energy of the photoelectrons is directly proportional to the frequency. - According to the quantum theory, when the intensity of the radiation increases, there is a proportional increase in the number of photons incident per second on the surface. One photon can cause the emission of one photoelectron. Therefore, with the increase in the intensity of radiation, there will be an increase in the photoelectron interactions and the rate of emission of electrons.
- The emission of a photoelectron is the result of a collision between a photon and an electron. As soon as the radiation is incident on the photosensitive surface, the entire energy of the photon is absorbed by the electron at once. Therefore, the electrons are emitted at a moment when light is incident on the metal surface. This explains why photoelectric emission is instantaneous.
- If the electron, with which the incident photon collides, is situated on the emitting surface, the electron will be ejected with maximum K.E as given by Einstein’s equation.
- If, however, the electron is situated in the interior of the emitting material, it will lose some energy in coming to the surface. This explains why the photoelectrons are emitted with different kinetic energies.
Thus, all the features of the photoelectric effect are explained.
APPEARS IN
संबंधित प्रश्न
If the frequency of incident light falling on a photosensitive material is doubled, then the kinetic energy of the emitted photoelectron will be ______.
What is the photoelectric effect?
Is it always possible to see the photoelectric effect with a red light?
Explain the inverse linear dependence of stopping potential on the incident wavelength in a photoelectric effect experiment.
Photocurrent recorded in the microammeter in an experimental setup of the photoelectric effect vanishes when the retarding potential is more than 0.8 V if the wavelength of incident radiation is 4950 Å. If the source of incident radiation is changed, the stopping potential turns out to be 1.2 V. Find the work function of the cathode material and the wavelength of the second source.
Define photoelectric effect.
The minimum frequency for photoelectric effect on metal is 7 × 1014 Hz, Find the work function of the metal.
Find the kinetic energy of the emitted electron, if in photoelectric effect energy of incident Photon is 4 eV and work function is 2.4 eV.
Find the energy of photon which have momentum 2 × 10-16 gm-cm/sec.
What is the photoelectric effect? Define stopping potential and photoelectric work function.
The ratio of energies of photons produced due to transition of electron of hydrogen atom from its (i) second to first energy level and (ii) highest energy level to second level is respectively.
When light falls on a metal surface, the maximum kinetic energy of the emitted photoelectrons depends upon ______
The maximum velocity of the photoelectron emitted by the metal surface is 'v '. Charge and mass of the photoelectron is denoted by 'e' and 'm' respectively. The stopping potential in volt is ______.
The work function of a metal is 1.6 x 10-19 J. When the metal surface is illuminated by the light of wavelength 6400 Å, then the maximum kinetic energy of emitted photo-electrons will be (Planck's constant h = 6.4 x 10-34 Js) ____________.
A metal surface is illuminated by photons of energy 5 eV and 2.5 eV respectively. The ratio of their wavelengths is ____________.
When certain metal surface is illuminated with a light of wavelength A., the stopping potential is V, When the same surface is illuminated by light of wavelength 2λ, the stopping potential is `("V"/3)`. The threshold wavelength for the surface is ______.
Light of different frequencies, whose photons have energies 3 eV and 18 eV respectively, successively illuminate a metal of work function 2 eV. The ratio of the maximum speeds of the emitted electrons will be ______.
Which one of the following statements ts INCORRECT for stopping potential in photoelectric emission?
The radiations of energies 1 eV and 2.5 eV are incident on a metal surface having work function 0.5 eV. The ratio of the maximum velocities of the emitted photo-electrons is ____________.
A metal surface having work function 'w0' emits photoelectrons when photons of energy 'E' are incident on it. The electron enters the uniform magnetic field (B) in perpendicular direction and moves in circular path of radius 'r'. Then 'r' is equal to (m and e be the mass and charge of electron respectively) ____________.
A light of frequency 'v' is incident on the metal surface whose threshold frequency is 'v0'. If v = v0, then [c = speed of light in medium] ____________.
In experiment of photoelectric effect, the stopping potential for incident yellow light of wavelength 5890 Å is 4 volt. If the yellow light is replaced by blue light of wavelength 4000 Å, the stopping potential is ____________.
The stopping potential in the context of photoelectric effect depends on the following property of incident electromagnetic radiation ______.
A point isotropic light source of power P = 12 watts is located on the axis of a circular mirror of radius R = 3 cm. If the distance of the source from the centre of the mirror is a = 39 cm and the reflection coefficient of the mirror is α = 0.70 then the force exerted by the light ray on the mirror is ______ × 10-10 N.
The photoelectric threshold for a certain metal surface is 3600 Å. If the metal surface is irradiated by a wavelength of 1100 Å, then kinetic energy of the emitted photoelectrons is ______.
Give Einstein's explanation of the photoelectric effect.
Draw a neat labelled diagram of photo-current as a function of accelerating potential for fixed incident intensity but different incident frequencies for the same emitter material.
In a photoelectric experiment, the stopping potential is 1.5V. What is the maximum kinetic energy of a photoelectron?