Advertisements
Advertisements
प्रश्न
The angles of the triangle are 3x – 40, x + 20 and 2x – 10 then the value of x is
विकल्प
40°
35°
50°
45°
उत्तर
35°
Explanation;
Hint:
3x – 40 + x + 20 + 2x – 10 = 180° ...(Sum of the angles of a triangle is 180°)
6x – 30 = 180°
6x = 180° + 30°
x = `(210^circ)/(6^circ)`
= 35°
APPEARS IN
संबंधित प्रश्न
The angles of a triangle are arranged in ascending order of magnitude. If the difference
between two consecutive angles is 10°, find the three angles.
If the bisectors of the base angles of a triangle enclose an angle of 135°, prove that the triangle is a right triangle.
If the bisector of the exterior vertical angle of a triangle be parallel to the base. Show that the triangle is isosce
Compute the value of x in the following figure:
In the given figure, if AB || CD, EF || BC, ∠BAC = 65° and ∠DHF = 35°, find ∠AGH.
In ΔPQR, If ∠R > ∠Q then ______.
Classify the following triangle according to angle:
The length of the sides of the triangle is given. Say what types of triangles they are 3 cm, 4 cm, 5 cm.
The length of the three segments is given for constructing a triangle. Say whether a triangle with these sides can be drawn. Give the reason for your answer.
9 cm, 6 cm, 16 cm
In figure, ∠BAC = 90° and AD ⊥ BC. The number of right triangles in the figure is ______.
