हिंदी

The domain and range of the real function f defined by f(x) = 4-xx-4 is given by ______. - Mathematics

Advertisements
Advertisements

प्रश्न

The domain and range of the real function f defined by f(x) = `(4 - x)/(x - 4)` is given by ______.

विकल्प

  • Domain = R, Range = {–1, 1}

  • Domain = R – {1}, Range = R

  • Domain = R – {4}, Range = {– 1}

  • Domain = R – {– 4}, Range = {–1, 1}

MCQ
रिक्त स्थान भरें

उत्तर

The domain and range of the real function f defined by f(x) = `(4 - x)/(x - 4)` is given by Domain = R – {4}, Range = {– 1}.

Explanation:

Given that: f(x) = `(4 - x)/(x - 4)`

We know that f(x) is defined if x – 4 ≠ 0

⇒ x ≠ 4

So, the domain of f(x) is = R – {4}

Let f(x) = y = `(4 - x)/(x - 4)`

⇒ yx – 4y = 4 – x

⇒ yx + x = 4y + 4

⇒ x(y + 1) = 4y + 4

⇒ x = `(4(1 + y))/(1 + y)`

If x is real number, then 1 + y ≠ 0

⇒ y ≠ – 1

∴ Range of f(x) = R {– 1}

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Relations and Functions - Exercise [पृष्ठ ३१]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
अध्याय 2 Relations and Functions
Exercise | Q 31 | पृष्ठ ३१

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Let A = {−2, −1, 0, 1, 2} and f : A → Z be a function defined by f(x) = x2 − 2x − 3. Find:

(b) pre-images of 6, −3 and 5.

 

Let f : R → R and g : C → C be two functions defined as f(x) = x2 and g(x) = x2. Are they equal functions?


fgh are three function defined from R to R as follow:

(i) f(x) = x2

Find the range of function.

 

Let X = {1, 2, 3, 4} and Y = {1, 5, 9, 11, 15, 16}
Determine which of the set are functions from X to Y.

(b) f2 = {(1, 1), (2, 7), (3, 5)}


Let A = [pqrs] and B = [1, 2, 3]. Which of the following relations from A to B is not a function?


If \[f\left( x \right) = \frac{2x}{1 + x^2}\] , show that f(tan θ) = sin 2θ.

 

 


Let f and g be two real functions defined by \[f\left( x \right) = \sqrt{x + 1}\] and \[g\left( x \right) = \sqrt{9 - x^2}\] . Then, describe function: 

(ii) g − 


Which of the following are functions?


f is a real valued function given by \[f\left( x \right) = 27 x^3 + \frac{1}{x^3}\] and α, β are roots of \[3x + \frac{1}{x} = 12\] . Then,

 
 

Check if the following relation is function:


If f(x) = `{(x^2 + 3","  x ≤ 2),(5x + 7","  x > 2):},` then find f(0)


Check if the relation given by the equation represents y as function of x:

x2 − y = 25


Express the area A of a square as a function of its perimeter P


Check the injectivity and surjectivity of the following function.

f : N → N given by f(x) = x2 


Express the following exponential equation in logarithmic form

e2 = 7.3890


Answer the following:

Let f: R → R be a function defined by f(x) = 5x3 – 8 for all x ∈ R, show that f is one-one and onto. Hence find f –1 


Answer the following:

Show that, `log ("a"^2/"bc") + log ("b"^2/"ca") + log ("c"^2/"ab")` = 0


Answer the following:

Find value of `(3 + log_10 343)/(2 + 1/2 log_10 (49/4) + 1/2 log_10 (1/25)`


Find the domain of the following function.

f(x) = `sqrtlog(x^2 - 6x + 6)`


A function f is defined by f(x) = 2x – 3 find x such that f(x) = x


A plane is flying at a speed of 500 km per hour. Express the distance ‘d’ travelled by the plane as function of time t in hour


The function f and g are defined by f(x) = 6x + 8; g(x) = `(x - 2)/3`

 Calculate the value of `"gg" (1/2)`


The range of the function f(x) = `(x - 3)/(5 - x)`, x ≠ 5 is ______.


The domain of the function f(x) = log3+x (x2 - 1) is ______.


Find the domain of the following functions given by f(x) = `(x^3 - x + 3)/(x^2 - 1)`


Find the range of the following functions given by f(x) = 1 + 3 cos2x

(Hint: –1 ≤ cos 2x ≤ 1 ⇒ –3 ≤ 3 cos 2x ≤ 3 ⇒ –2 ≤ 1 + 3cos 2x ≤ 4)


Let f(x) = `sqrt(1 + x^2)`, then ______.


The domain of the function f given by f(x) = `(x^2 + 2x + 1)/(x^2 - x - 6)` is ______.


The range of the function y = `1/(2 - sin3x)` is ______.


The period of the function

f(x) = `(sin 8x cos x - sin 6x cos 3x)/(cos 2x cos x - sin 3x sin 4x)` is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×