हिंदी

The reaction between HX2(g) and OX2(g) is highly feasible yet allowing the gases to stand at room temperature in the same vessel does not lead to the formation of water. Explain. - Chemistry

Advertisements
Advertisements

प्रश्न

The reaction between \[\ce{H2(g)}\] and \[\ce{O2(g)}\] is highly feasible yet allowing the gases to stand at room temperature in the same vessel does not lead to the formation of water. Explain.

टिप्पणी लिखिए

उत्तर

\[\ce{2H2(g) + O2(g) -> 2H2O(I)}\]

This reaction does not take place at room because the activation energy of the reaction is very high.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Chemical Kinetics - Exercises [पृष्ठ ५६]

APPEARS IN

एनसीईआरटी एक्झांप्लर Chemistry [English] Class 12
अध्याय 4 Chemical Kinetics
Exercises | Q III. 43. | पृष्ठ ५६

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

(b) Rate constant ‘k’ of a reaction varies with temperature ‘T’ according to the equation:

`logk=logA-E_a/2.303R(1/T)`

Where Ea is the activation energy. When a graph is plotted for `logk Vs. 1/T` a straight line with a slope of −4250 K is obtained. Calculate ‘Ea’ for the reaction.(R = 8.314 JK−1 mol−1)


The rate constant of a first order reaction increases from 4 × 10−2 to 8 × 10−2 when the temperature changes from 27°C to 37°C. Calculate the energy of activation (Ea). (log 2 = 0.301, log 3 = 0.4771, log 4 = 0.6021)


The rate constant for the first-order decomposition of H2O2 is given by the following equation:

`logk=14.2-(1.0xx10^4)/TK`

Calculate Ea for this reaction and rate constant k if its half-life period be 200 minutes.

(Given: R = 8.314 JK–1 mol–1)


The rate of the chemical reaction doubles for an increase of 10 K in absolute temperature from 298 K. Calculate Ea.


The decomposition of A into product has value of k as 4.5 × 103 s−1 at 10°C and energy of activation 60 kJ mol−1. At what temperature would k be 1.5 × 104 s−1?


The rate of a reaction quadruples when the temperature changes from 293 K to 313 K. Calculate the energy of activation of the reaction assuming that it does not change with temperature.


Which of the following graphs represents exothermic reaction?

(a)  

(b)  

(c)  


Mark the incorrect statements:

(i) Catalyst provides an alternative pathway to reaction mechanism.

(ii) Catalyst raises the activation energy.

(iii) Catalyst lowers the activation energy.

(iv) Catalyst alters enthalpy change of the reaction.


Why does the rate of a reaction increase with rise in temperature?


In respect of the eqn k = \[\ce{Ae^{{-E_a}/{RT}}}\] in chemical kinetics, which one of the following statement is correct?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×