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The unit vector normal to the plane x + 2y +3z – 6 = 0 is ijk114i^+214j^+314k^. - Mathematics

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प्रश्न

The unit vector normal to the plane x + 2y +3z – 6 = 0 is `1/sqrt(14)hat"i" + 2/sqrt(14)hat"j" + 3/sqrt(14)hat"k"`.

विकल्प

  • True

  • False

MCQ
सत्य या असत्य

उत्तर

This statement is True.

Explanation:

Given plane is x + 2y + 3z – 6 = 0

Vector normal to the plane `vec"n" = hat"i" + 2hat"j" + 3hat"k"`

∴ `hat"n" = vec"n"/|vec"n"|`

= `(hat"i" + 2hat"j" + 3hat"k")/sqrt((1)^2 + (2)^2 + (3)^2`

= `1/sqrt(14)hat"i" + 2/sqrt(14)hat"j" + 3/sqrt(14)hat"k"`

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अध्याय 11: Three Dimensional Geometry - Exercise [पृष्ठ २३९]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
अध्याय 11 Three Dimensional Geometry
Exercise | Q 42 | पृष्ठ २३९

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