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प्रश्न
In following cases, determine the direction cosines of the normal to the plane and the distance from the origin.
x + y + z = 1
उत्तर
x + y + z = 1 … (1)
The direction ratios of normal are 1, 1, and 1.
This equation is of the form lx + my + nz = d, where l, m, n are the direction cosines of normal to the plane and d is the distance of normal from the origin.
Therefore, the direction cosines of the normal are `1/sqrt3, 1/sqrt3 and 1/sqrt3` the distance of normal from the origin is `1/sqrt3` units.
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संबंधित प्रश्न
In following cases, determine the direction cosines of the normal to the plane and the distance from the origin.
2x + 3y – z = 5
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