Advertisements
Advertisements
प्रश्न
There are two paths that one can choose to go from Sarah’s house to James's house. One way is to take C street, and the other way requires to take B street and then A street. How much shorter is the direct path along C street?
उत्तर
Distance between Sarah’s House and James’s House using “C street”.
AC2 = AB2 + BC2
= 22 + 1.52
= 4 + 2.25
= 6.25
AC = `sqrt(6.25)`
AC = 2.5 miles
Distance covered by using “A Street” and “B Street”
= (2 + 1.5) miles
= 3.5 miles
Difference in distance = 3.5 miles – 2.5 miles = 1 mile
APPEARS IN
संबंधित प्रश्न
A man goes 10 m due east and then 24 m due north. Find the distance from the starting point
If ABC is an equilateral triangle of side a, prove that its altitude = ` \frac { \sqrt { 3 } }{ 2 } a`
Identify, with reason, if the following is a Pythagorean triplet.
(4, 9, 12)
In Fig. 3, ∠ACB = 90° and CD ⊥ AB, prove that CD2 = BD x AD.
In the given figure, angle ADB = 90°, AC = AB = 26 cm and BD = DC. If the length of AD = 24 cm; find the length of BC.
A ladder, 6.5 m long, rests against a vertical wall. If the foot of the ladder is 2.5 m from the foot of the wall, find up to how much height does the ladder reach?
The sides of the triangle are given below. Find out which one is the right-angled triangle?
11, 60, 61
A 5 m long ladder is placed leaning towards a vertical wall such that it reaches the wall at a point 4 m high. If the foot of the ladder is moved 1.6 m towards the wall, then find the distance by which the top of the ladder would slide upwards on the wall.
In an equilateral triangle PQR, prove that PS2 = 3(QS)2.
The hypotenuse (in cm) of a right angled triangle is 6 cm more than twice the length of the shortest side. If the length of third side is 6 cm less than thrice the length of shortest side, then find the dimensions of the triangle.