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Three Equal Charges, 2.0 × 10−6 C Each, Are Held at the Three Corners of an Equilateral Triangle of Side 5 Cm. Find the Coulomb Force Experienced by One of the Charges Due to the Other Two. - Physics

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प्रश्न

Three equal charges, 2.0 × 106 C each, are held at the three corners of an equilateral triangle of side 5 cm. Find the Coulomb force experienced by one of the charges due to the other two.  

टिप्पणी लिखिए

उत्तर

Since all the charges are of equal magnitude, the force on the charge at A due to the charges at B and C will be of equal magnitude. (As shown in the figure) 

That is,

\[F_{BA}  =  F_{CA}  = F\left( \text{ say } \right)\]
 
 
 
The horizontal components of force cancel each other and the net force on the charge at A,

\[F' =  F_{BA} \sin\theta +  F_{CA} \sin\theta\] 

\[F' = 2F\sin\theta  \] 

Given: r = 5 cm =0.05 m
By Coulomb's Law, force, 

\[F = \frac{1}{4\pi \epsilon_0}\frac{q_1 q_2}{r^2}\]

\[F' = \frac{2 \times 9 \times {10}^9 \times \left( 2 \times {10}^{- 6} \right)^2 \times \sin60^\circ}{\left( 0 . 05 \right)^2}\] 

\[F' = \frac{2 \times 9 \times {10}^9 \times \left( 2 \times {10}^{- 6} \right)^2 \times \frac{\sqrt{3}}{2}}{\left( 0 . 05 \right)^2}\]

F' = 24.9 N

 
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अध्याय 7: Electric Field and Potential - Exercises [पृष्ठ १२१]

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एचसी वर्मा Concepts of Physics Vol. 2 [English] Class 11 and 12
अध्याय 7 Electric Field and Potential
Exercises | Q 16 | पृष्ठ १२१

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