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प्रश्न
Write symbolically the process expressing the β+ decay of `""_11^22Na`. Also write the basic nuclear process underlying this decay.
उत्तर
The β+ decay for `""_11^22Na` is given below:
`""_11^22Na->_10^22Ne+beta^++v`
If the unstable nucleus has excess protons than required for stability, a proton converts itself into a neutron. In the process, a positron e+ (or a β+) and a neutrino ν are created and emitted from the nucleus.
p→n+β++ν
This process is called beta plus decay.
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संबंधित प्रश्न
State the law of radioactive decay.
The decay constant of a radioactive sample is λ. The half-life and the average-life of the sample are respectively
The masses of 11C and 11B are respectively 11.0114 u and 11.0093 u. Find the maximum energy a positron can have in the β*-decay of 11C to 11B.
(Use Mass of proton mp = 1.007276 u, Mass of `""_1^1"H"` atom = 1.007825 u, Mass of neutron mn = 1.008665 u, Mass of electron = 0.0005486 u ≈ 511 keV/c2,1 u = 931 MeV/c2.)
Calculate the maximum kinetic energy of the beta particle emitted in the following decay scheme:
12N → 12C* + e+ + v
12C* → 12C + γ (4.43MeV).
The atomic mass of 12N is 12.018613 u.
(Use Mass of proton mp = 1.007276 u, Mass of `""_1^1"H"` atom = 1.007825 u, Mass of neutron mn = 1.008665 u, Mass of electron = 0.0005486 u ≈ 511 keV/c2,1 u = 931 MeV/c2.)
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