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Write the general form of a 3 × 3 skew-symmetric matrix and prove that its determinant is 0 - Mathematics

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प्रश्न

Write the general form of a 3 × 3 skew-symmetric matrix and prove that its determinant is 0

योग

उत्तर

Let A = `[(0, "a", "b"),(-"a", 0, -"c"),(-"b", "c", 0)]`

Here AT = `[(0, -"a", -"b"),("a", 0, "c"),("b", -"c", 0)]`

= – A

⇒ A is a skew symmetric matrix

Now |A| = `|(0, "a", "b"),(-"a", 0, -"c"),(-"b", "c", 0)|`

= 0(0 + c2) – a[0 – bc] + b[– ac + 0]

= abc – abc

= 0

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Determinants
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Matrices and Determinants - Exercise 7.2 [पृष्ठ २९]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 7 Matrices and Determinants
Exercise 7.2 | Q 7 | पृष्ठ २९

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