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प्रश्न
A circular park has a path of uniform width around it. The difference between the outer and inner circumferences of the circular path is 132 m. Its width is
पर्याय
20 m
21 m
22 m
24 m
उत्तर
Let OA = r be the radius of the inner circle and OB = r′ be the radius of the outer circle.
Therefore, circumference of the inner circle =`2pir` and circumference of the outer circle`=2pir'`
Here we have to find the width of the circular park that is we have to find `r'-r.`.
We have given the difference between the circumferences of outer circle and inner circle.
`∴ 2pir'-2pir=132`
`∴2pi(r'-r)=132`
Substituting `pi=22/7` we get,
`2xx22/7xx(r'-r)=132`
Now we will multiply both sides of the equation by `7/44`
`(r'-r)=132xx7/44`
`∴(r'-r)=3xx7`
`∴(r'-r)=21`
Therefore, the width is`21 m`.
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