Advertisements
Advertisements
प्रश्न
A path of width 3.5 m runs around a semi-circular grassy plot whose perimeter is 72 m . Find the area of the path .
`("Use" pi= 22/7) `
उत्तर
Let the radius of the semicircular plot be r.
Perimeter of the semi-circular grassy plot = `pi r+2r=72`
`⇒ r=14 cm`
Given that the width of the plot = 3.5 m
Thus, the outer radius = 3.5 + 14 = 17.5 m
Area of the path = `(pi R^2)/2-(pi r^2)/2`
`= pi/2 (R^2-r^2)`
`=pi/2 ((17.5)^2-(14)^2)`
`= 173.25 m^2`
APPEARS IN
संबंधित प्रश्न
The length of the minute hand of a clock is 14 cm. Find the area swept by the minute hand in 5 minutes.
In a circle of radius 21 cm, an arc subtends an angle of 60° at the centre. Find the area of the sector formed by the arc. (Use π = `22/7`)
Find the ratio of the area of the circle circumscribing a square to the area of the circle inscribed in the square .
If the area of a circle is equal to the sum of the areas of two circles of diameters 10 cm and 24 cm, then diameter of the large circle (in cm) is
A square is inscribed in a circle. Find the ratio of the areas of the circle and the square.
In the given figure, PQRS represents a flower bed. If OP = 21 m and OR = 14 m, find the area of the flower bed.
The area of circle is equal to the sum of the areas of two circles of radii 24 cm and 7 cm. The diameter of the new circle is
In the given figure, a square OABC has been inscribed in the quadrant OPBQ. If OA = 20 cm, then the area of the shaded region is
The area of the circle that can be inscribed in a square of side 6 cm is ______.
A circular park is surrounded by a road 21 m wide. If the radius of the park is 105 m, find the area of the road.