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प्रश्न
ABCD is a square of side 4 cm. If E is a point in the interior of the square such that ΔCEDis equilateral, then area of Δ ACE is
पर्याय
\[2\sqrt{3} - 1 c m^2\]
\[4\sqrt{3} - 1 c m^2\]
\[6\sqrt{3} - 1 c m^2\]
\[8\sqrt{3} - 1 c m^2\]
उत्तर
We have the following diagram.
Since `ΔCED` is equilateral,
Therefore,
`EC=CD=DE=4 cm`
Now, `∠ ECD=60°`
Since AC is diagonal of sqr.ABCD
Therefore,
`∠ACD=45°`
Therefore we get,
`∠ECA=∠ECD-∠ACD`
`=60°-45°`
`=15°`
Now, in `ΔACE`, draw a perpendicular EM to the base AC.
So in `Δ EMC`
`sin 15°=(EM)/(EC)`
`=(EM)/4`
Therefore,
`EM=sqrt2(sqrt3-1)`
Now in `ΔAEC`
ar `(ΔAEC=1/2) (AC)(EM)`
`=4(sqrt3-1)cm^2`
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