मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Check whether the conditions of Rolle’s theorem are satisfied by the function f (x) = (x - 1) (x - 2) (x - 3), x ∈ [1, 3] - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

Check whether the conditions of Rolle’s theorem are satisfied by the function
f (x) = (x - 1) (x - 2) (x - 3), x ∈ [1, 3]

उत्तर

`f(x)=(x-1)(x-2)(x-3),`          `x in[1, 3]`

`=x^3-6x^2+11x-6`

As f(x) is a polynomial function, it is continuous and differentiable everywhere on its domain. Thus,
a. f(x) is continuous on [1, 3]
b. f(x) is differentiable on (1, 3)

Further, f(1) = 0 and f(3) = 0
∴ f(1) = f(3)

Thus, all the conditions of Rolle’s theorem are satisfied.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
2016-2017 (July)

APPEARS IN

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

Verify Lagrange’s mean value theorem for the function f(x)=x+1/x, x ∈ [1, 3]


Verify Mean Value Theorem, if f (x) = x2 – 4x – 3 in the interval [a, b], where a = 1 and b = 4.


Verify Mean Value Theorem, if f (x) = x3 – 5x2 – 3x in the interval [a, b], where a = 1 and b = 3. Find all c ∈ (1, 3) for which f ′(c) = 0.


Examine the applicability of Mean Value Theorem for all three functions given in the above exercise 2. 


Verify Rolle’s theorem for the following function:

`f(x) = e^(-x) sinx " on"  [0, pi]`


f(x) = (x-1)(x-2)(x-3) , x ε[0,4], find if 'c' LMVT can be applied


Verify the Lagrange’s mean value theorem for the function: 
`f(x)=x + 1/x ` in the interval [1, 3]


Verify Langrange’s mean value theorem for the function:

f(x) = x (1 – log x) and find the value of  c in the interval [1, 2].


Verify Mean value theorem for the function f(x) = 2sin x + sin 2x on [0, π].


Verify Rolle’s theorem for the function, f(x) = sin 2x in `[0, pi/2]`.


Verify mean value theorem for the function f(x) = (x – 3)(x – 6)(x – 9) in [3, 5].


The value of c in Rolle’s Theorem for the function f(x) = e x sinx, x ∈ π [0, π] is ______.


The value of c in Mean value theorem for the function f(x) = x(x – 2), x ∈ [1, 2] is ______.


f(x) = x(x – 1)2 in [0, 1]


f(x) = log(x2 + 2) – log3 in [–1, 1]


f(x) = `x(x + 3)e^((–x)/2)` in [–3, 0]


f(x) = `sqrt(4 - x^2)` in [– 2, 2]


Discuss the applicability of Rolle’s theorem on the function given by f(x) = `{{:(x^2 + 1",",  "if"  0 ≤ x ≤ 1),(3 - x",",  "if"  1 ≤ x ≤ 2):}`


f(x) = `1/(4x - 1)` in [1, 4]


f(x) = x3 – 2x2 – x + 3 in [0, 1]


Find a point on the curve y = (x – 3)2, where the tangent is parallel to the chord joining the points (3, 0) and (4, 1)


A value of c for which the Mean value theorem holds for the function f(x) = logex on the interval [1, 3] is ____________.


The value of c in mean value theorem for the function f(x) = (x - 3)(x - 6)(x - 9) in [3, 5] is ____________.


If the greatest height attained by a projectile be equal to the horizontal range, then the angle of projection is


Rolle's Theorem holds for the function x3 + bx2 + cx, 1 ≤ x ≤ 2 at the point `4/3`, the value of b and c are


P(x) be a polynomial satisfying P(x) – 2P'(x) = 3x3 – 27x2 + 38x + 1.

If function

f(x) = `{{:((P^n(x) + 18)/6, x ≠ π/2),(sin^-1(ab) + cos^-1(a + b - 3ab), x = π/2):}`

is continuous at x = ` π/2`, then (a + b) is equal to ______.


Let f(1) = –2 and f'(x) ≥ 4.2 for 1 ≤ x ≤ 6. The possible value of f(6) lies in the interval ______. 


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×