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प्रश्न
Consider the following frequency distribution :
| Class: | 0-5 | 6-11 | 12-17 | 18-23 | 24-29 |
| Frequency: | 13 | 10 | 15 | 8 | 11 |
The upper limit of the median class is
पर्याय
17
17.5
18
18.5
उत्तर
The given classes in the table are non-continuous. So, we first make the classes continuous by adding 0.5 to the upper limit and subtracting 0.5 from the lower limit in each class.
| Class | Frequency | Cumulative Frequency |
| 0.5–5.5 | 13 | 13 |
| 5.5–11.5 | 10 | 23 |
| 11.5–17.5 | 15 | 38 |
| 17.5–23.5 | 8 | 46 |
| 23.5–29.5 | 11 | 57 |
Now, from the table we see that N = 57.
So,
\[\frac{N}{2} = \frac{57}{2} = 28 . 5\]
28.5 lies in the class 11.5–17.5.
The upper limit of the interval 11.5–17.5 is 17.5.
Hence, the correct answer is option (b).
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