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Consider the matrix Aα = [cosα-sinαsinαcosα] Show that AAAAαAβ=A(α+β) - Mathematics

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प्रश्न

Consider the matrix Aα = `[(cos alpha, - sin alpha),(sin alpha, cos alpha)]` Show that `"A"_alpha "A"_beta = "A"_((alpha + beta))`

बेरीज

उत्तर

`"A"_alpha "A"_beta = [(cos alpha, - sin alpha),(sin alpha, cos alpha)] [(cos beta, - sin beta),(sin beta, cos beta)]`

= `[(cos alpha cos beta - sin alpha sin beta, - cos alpha sin beta - sin alpha cos beta),(sin alpha cos beta + cos alpha sin beta, - sin alpha sin beta + cos alpha cos beta)]`

= `[(cos alpha cos beta - sin alpha sin beta, -(sinalpha cos beta + cos alpha sin beta)),(sin alpha cos beta + cos alpha sin beta, cos alpha cos beta - sin alpha sin beta)]`

`"A"_alpha "A"_beta = [(cos(alpha + beta), - sin(alpha + beta)),(sin(alpha + beta) , cos(alpha + beta))]`

From equation (1), (2) and (3)

`"A"_alpha "A"_beta = "A"_((alpha + beta))`

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Matrices
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: Matrices and Determinants - Exercise 7.1 [पृष्ठ १८]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 7 Matrices and Determinants
Exercise 7.1 | Q 6. (i) | पृष्ठ १८

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