मराठी

Determine the area under the curve y = aa2-x2 included between the lines x = 0 and x = a. - Mathematics

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प्रश्न

Determine the area under the curve y = `sqrt("a"^2 - x^2)` included between the lines x = 0 and x = a.

बेरीज

उत्तर


Here, we are given y = `sqrt("a"^2 - x^2)`

⇒ y2 = a2 – x2

⇒ x2 + y2 = a2

Area of the shaded region

= `2[(1)^(3/2) - 0] - 3/2[(1)^2 - 0]`

= `[x/2 sqrt("a"^2 - x^2) + "a"^2/2 sin^-1  x/"a"]_0^"a"`

= `["a"/2 sqrt("a"^2 - "a"^2) + "a"^2/2 sin^-1  "a"/"a" - 0 - 0]`

= `"a"^2/2 sin^-1 (1)`

= `"a"^2/2 * pi/2`

= `(pi"a"^2)/4`

Hence, the required area = `(pi"a"^2)/4` sq.units.

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पाठ 8: Application Of Integrals - Exercise [पृष्ठ १७७]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
पाठ 8 Application Of Integrals
Exercise | Q 12 | पृष्ठ १७७

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