मराठी

The Area of the Circle X2 + Y2 = 16 Exterior to the Parabola Y2 = 6x Is - Mathematics

Advertisements
Advertisements

प्रश्न

Choose the correct answer The area of the circle x2 + y2 = 16 exterior to the parabola y2 = 6x is

A. `4/3 (4pi - sqrt3)`

B. `4/3 (4pi + sqrt3)`

C. `4/3 (8pi - sqrt3)`

D.`4/3 (4pi + sqrt3)`

उत्तर

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 8: Application of Integrals - Exercise 8.3 [पृष्ठ ३७६]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 12
पाठ 8 Application of Integrals
Exercise 8.3 | Q 18 | पृष्ठ ३७६

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Using integration, find the area of the region bounded by the triangle whose vertices are (−1, 2), (1, 5) and (3, 4).


Find the area of the region lying between the parabolas y2 = 4ax and x2 = 4ay.


Find the area of the region bounded by the curves y = x+ 2, xx = 0 and x = 3


Using integration find the area of the triangular region whose sides have the equations y = 2x +1, y = 3x + 1 and = 4.


Smaller area enclosed by the circle x2 + y2 = 4 and the line x + y = 2 is

A. 2 (π – 2)

B. π – 2

C. 2π – 1

D. 2 (π + 2)


Area lying between the curve y2 = 4x and y = 2x is

A. 2/3

B. 1/3

C. 1/4

D. 3/4


Using the method of integration find the area bounded by the curve |x| + |y| = 1 .

[Hint: The required region is bounded by lines x + y = 1, x– y = 1, – x + y = 1 and
– x – y = 1].


Find the area bounded by curves {(x, y) : y ≥ x2 and y = |x|}.


Using integration, find the area of region bounded by the triangle whose vertices are (–2, 1), (0, 4) and (2, 3).


Show that the rectangle of the maximum perimeter which can be inscribed in the circle of radius 10 cm is a square of side `10sqrt2` cm.


Find the area included between the parabolas y2 = 4ax and x2 = 4by.


The area enclosed between the curves y = loge (x + e), x = log\[\left( \frac{1}{y} \right)\] and the x-axis is _______ .


The area between x-axis and curve y = cos x when 0 ≤ x ≤ 2 π is ___________ .


Area lying between the curves y2 = 4x and y = 2x is


The area of the region included between the parabolas y2 = 16x and x2 = 16y, is given by ______ sq.units


The area enclosed between the two parabolas y2 = 20x and y = 2x is ______ sq.units


The area of triangle ΔABC whose vertices are A(1, 1), B(2, 1) and C(3, 3) is ______ sq.units


Find the area enclosed between y = cos x and X-axis between the lines x = `pi/2` and x ≤ `(3pi)/2`


Find the area of the ellipse `x^2/36 + y^2/64` = 1, using integration


Find the area of the region included between y = x2 + 5 and the line y = x + 7


Find the area enclosed between the circle x2 + y2 = 9, along X-axis and the line x = y, lying in the first quadrant


Find the area of the region included between the parabola y = `(3x^2)/4` and the line 3x – 2y + 12 = 0.


Find the area of a minor segment of the circle x2 + y2 = a2 cut off by the line x = `"a"/2`


Calcualte the area under the curve y = `2sqrt(x)` included between the lines x = 0 and x = 1


Draw a rough sketch of the curve y = `sqrt(x - 1)` in the interval [1, 5]. Find the area under the curve and between the lines x = 1 and x = 5.


Determine the area under the curve y = `sqrt("a"^2 - x^2)` included between the lines x = 0 and x = a.


The value of a for which the area between the curves y2 = 4ax and x2 = 4ay is 1 sq.unit, is ______.


Using Integration, find the area of triangle whose vertices are (– 1, 1), (0, 5) and (3, 2).


Find the area cut off from the parabola 4y = 3x2 by the line 2y = 3x + 12.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×